A juggler performs in a room whose ceiling is $3$ m above the level of his hands. He throws a ball vertically upward so that it just reaches the ceiling.
(a) With what initial velocity does he throw the ball?

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Solution

Maximum height reached by ball $h = 3 m$
Initial speed $u = \sqrt{2 g h} = \sqrt{2 \times 10 \times 3} = 7.75 m / s$

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A juggler performs in a room whose ceiling is 3m above the level of his hands. He throws a ball vertically upward so that it just reaches the ceiling.(a) With what initial velocity does he throw the ball?

Maximum height reached by ball h=3 mInitial speed u=√2gh=√2×10×3=7.75 m/s

A juggler performs in a room whose ceiling is $3$ m above the level of his hands. He throws a ball vertically upward so that it just reaches the ceiling.
(a) With what initial velocity does he throw the ball?

Maximum height reached by ball $h = 3 m$
Initial speed $u = \sqrt{2 g h} = \sqrt{2 \times 10 \times 3} = 7.75 m / s$