A Juggler throws balls into air. He throws one whenever the previous is at its highest point. If he throws n balls each second, the height to which each balls will rise is
A
g2n2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
gn2
No worries! Weāve got your back. Try BYJUāS free classes today!
C
2g2n
No worries! Weāve got your back. Try BYJUāS free classes today!
D
2g2n
No worries! Weāve got your back. Try BYJUāS free classes today!
Open in App
Solution
The correct option is Ag2n2 Time taken by each ball to reach max height is t=1n
At maximum height, v=0
So, from first equation of motion v=u+at ⇒0=u–g1n ⇒u=gn
Also, from third equation of motion, we get v2=u2+2aHmax ⇒0=g2n2−2gHmax ⇒Hmax=g2n2
Hence, the height to which each balls will rise is Hmax=g2n2