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Question

A juice seller in marriage party has a cylindrical vessel with base radius 25 CM and height 40 CM full of juice . He gives same in small glasses of radius 5 CM and height 10 CM. How many oranges are required to fill, it complete if to fill one small glass two oranges are required

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Solution

Given radius and height of cylindrical vessel is 25 cm and 40 cm respectively.
Radius and height of glass is 5 cm and 10 cm respectively.
No. of oranges = 2 x no. of small glasses

Volume of cylindrical =πr2h

So, no. of small glass =TotalvolumeofjuiceVolumeofonesmallglass
=π×(25)2×40π×52×10
=25×25×4025×10
=100 glasses

No of oranges required = 2 x 100= 200 oranges

Therefore, 200 oranges required.


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