Question

A juice seller in marriage party has a cylindrical vessel with base radius 25 CM and height 40 CM full of juice . He gives same in small glasses of radius 5 CM and height 10 CM. How many oranges are required to fill, it complete if to fill one small glass two oranges are required

Answer 1

Given radius and height of cylindrical vessel is 25 cm and 40 cm respectively.
Radius and height of glass is 5 cm and 10 cm respectively.
No. of oranges = 2 x no. of small glasses

Volume of cylindrical =$\pi r^{2}h$

So, no. of small glass =$\frac{Totalvolumeofjuice}{Volumeofonesmallglass}$
$=\frac{\pi \times (25{)}^2\times 40}{\pi \times 5^2\times 10}$
$=\frac{25\times 25\times 40}{25\times 10}$
$=100$ glasses

No of oranges required = 2 x 100= 200 oranges

Therefore, 200 oranges required.