Question

A junction diode has a resistance of $25\Omega$ when forward biased and $2500\Omega$ when reverse biased. The current in the diode, for the arrangement shown will be

• A. $\frac{1}{15}A$
• B. $\frac{1}{7}A$
• C. $\frac{1}{25}A$
• D. $\frac{1}{180}A$

Answer 1

The correct option is B $\frac{1}{7}A$

The junction diode is forward biased.
Therefore, the effective resistance $=25+10=35\Omega$
$\therefore$ Current in diode $I=\frac{5V}{35\Omega }=\frac{1}{7}A$