Question

A king divides his property among his $3$ sons such that the eldest son's share is double the second son's share and the share of the second son is triple the third son's share. If the second son gets $Rs4000$ more than the third, find the value of the total property.

• A. $Rs10000$
• B. $Rs20000$
• C. $Rs5000$
• D. $Rs2000$

Answer 1

The correct option is B

$Rs20000$

Let the third son’s share be $x$.

Then second son’s share $=4,000+x$

Also given that the share of the second son is triple the third son’s share

$$\begin{gathered} 4,000+x=3x \\ \Rightarrow 3x-x=4,000 \\ \Rightarrow 2x=4,000 \\ \Rightarrow x=\frac{4,000}{2} \\ \Rightarrow x=2,000 \end{gathered}$$

So the second son’s share $=4,000+x=4,000+2,000=Rs6,000$.

Elder son share$=$double the share of the second son$=2\times 6,000=Rs12,000$.

The value of the total property$=2,000+6,000+12,000=Rs20,000$.

Hence, option B is the correct answer.