One shaded portion is ΔABD.\)
=(12×BD×AO)=(12×32×16) cm2
=256 cm2
Second shaded portion is ΔBCD
ar(ΔBCD)=ar(ΔABD)=256 cm2
Third shaded portion is CEF in which CE = CF = 6cm and EF = 8cm.
∴s=12(6+6+8)=10, (s−a)=4, (s−b)=4, (s−c)=2
∴ar(ΔCEF)=√10×4×4×2=8√5
=(8×2.24) cm2=17.92 cm2