A kite is attached to a string. Find the length of the string, when the height of the kite is 60 m and the string makes an angle $30^{\circ}$ with the ground.

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Solution

$s i n θ$ = $\frac{p e r p e n d i c u l a r s i d e}{h y p o t e n u s e}$

$s i n 30^{o}$ = $\frac{60}{x}$ (let the string lenth x)

$\frac{1}{2}$ = $\frac{60}{x}$

so x (the string length) is 60 X 2 =120 m.

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A kite is attached to a string. Find the length of the string, when the height of the kite is 60 m and the string makes an angle 30∘ with the ground.

sinθ=perpendicular sidehypotenuse sin30o =60x (let the string lenth x) 12 = 60x so x (the string length) is 60 X 2 =120 m.

A kite is attached to a string. Find the length of the string, when the height of the kite is 60 m and the string makes an angle $30^{\circ}$ with the ground.

$s i n θ$ = $\frac{p e r p e n d i c u l a r s i d e}{h y p o t e n u s e}$

$s i n 30^{o}$ = $\frac{60}{x}$ (let the string lenth x)

$\frac{1}{2}$ = $\frac{60}{x}$

so x (the string length) is 60 X 2 =120 m.