Question

A kite is flying at a height of 60 m above the ground. The string attached to the kite is tied at the ground. It makes an angle of 60° with the ground. Assuming that the string is straight, find the length of the string. $\left(\sqrt{3}=1.73\right)$

Answer 1

Let AB be the height of kite above the ground and C be the position of the string attached to the kite which is tied at the ground.

Suppose the length of the string be x m.



Here, AB = 60 m and ∠ACB = 60º

In right ∆ABC,

$$\begin{gathered} \sin 60°=\frac{\mathrm{AB}}{\mathrm{AC}} \\ \Rightarrow \frac{\sqrt{3}}{2}=\frac{60}{x} \\ \Rightarrow x=\frac{120}{\sqrt{3}}=40\sqrt{3} \\ \Rightarrow x=40\times 1.73=69.2\mathrm{m} \end{gathered}$$
Thus, the length of the string is 69.2 m.