Question

A kite is flying at a height of 75 m from the level ground, attached to a string inclined at ${60}^{\circ }$ to the horizontal. Find the length of the string, assuming that there is no slack in it. [Take $\sqrt{3}$=1.732].

Answer 1

Given

Height of kite from ground ,$AB=75m$

The inclination of string with ground $\theta ={60}^o$

Length of string,$L=AC$

If we represent the above data in form of the figure as shown it forms a right angle triangle $\Delta ABC$

Here,

$\sin \theta =\frac{oppositeside}{hypotenuse}\sin {60}^o=\frac{AB}{AC}\frac{\sqrt{3}}{2}=\frac{75}{L}L=150\sqrt{3}mLengthofstring,L=\frac{150}{\sqrt{3}}m=\frac{150}{1.732}=86.60m$