A kite is flying on a string of 20 $\sqrt{3}$ m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is $60^{\circ}$ . The height at which the kite is flying is 20 m.

60√3

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Solution

The correct option is B
60

$s i n ∠ A C B = \frac{A B}{A C} \Rightarrow s i n 60^{\circ} = \frac{A B}{A C} \Rightarrow s i n 60^{\circ} . A C = A B = 20 \sqrt{3} \times \frac{\sqrt{3}}{2} ∴ Height of the kite is 30 m .$

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A kite is flying on a string of 20√3m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60∘. The height at which the kite is flying is 20 m.

The correct option is B 60 sin∠ACB=ABAC⇒sin60∘=ABAC⇒sin60∘.AC=AB=20√3×√32∴Height of the kite is 30m.

A kite is flying on a string of 20 $\sqrt{3}$ m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is $60^{\circ}$ . The height at which the kite is flying is 20 m.

The correct option is B
60

$s i n ∠ A C B = \frac{A B}{A C} \Rightarrow s i n 60^{\circ} = \frac{A B}{A C} \Rightarrow s i n 60^{\circ} . A C = A B = 20 \sqrt{3} \times \frac{\sqrt{3}}{2} ∴ Height of the kite is 30 m .$