A kite is flying on a string of 40 m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is $30^{\circ}$ . Find the height at which the kite is flying.

10 m

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30 m

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20 m

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40 m

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Solution

The correct option is C
20 m

The situation can be represented by the figure below:

AB is the height at which the kite is flying.
$s i n (∠ A C B) = \frac{A B}{A C} \Rightarrow s i n 30^{\circ} = \frac{A B}{A C} \Rightarrow \frac{1}{2} \times 40 = A B \Rightarrow A B = 20 m$

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A kite is flying on a string of 40 m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 30∘. Find the height at which the kite is flying.

The correct option is C 20 m The situation can be represented by the figure below: AB is the height at which the kite is flying. sin(∠ACB)=ABAC⇒sin30∘=ABAC⇒12×40=AB⇒AB=20m

A kite is flying on a string of 40 m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is $30^{\circ}$ . Find the height at which the kite is flying.

The correct option is C
20 m

The situation can be represented by the figure below:

AB is the height at which the kite is flying.
$s i n (∠ A C B) = \frac{A B}{A C} \Rightarrow s i n 30^{\circ} = \frac{A B}{A C} \Rightarrow \frac{1}{2} \times 40 = A B \Rightarrow A B = 20 m$