A kite is flying on a string of 40 m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is $30^{\circ}$ . Find the height at which the kite is flying.
20

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Solution

The correct option is A 20

AB is the height at which the kite is flying.
$s i n (∠ A C B) = \frac{A B}{A C} \Rightarrow s i n 30^{\circ} = \frac{A B}{A C} \Rightarrow \frac{1}{2} \times 40 = A B \Rightarrow A B = 20 m$

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A kite is flying on a string of 40 m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 30∘. Find the height at which the kite is flying.20

The correct option is A 20 AB is the height at which the kite is flying. sin(∠ACB)=ABAC⇒sin30∘=ABAC⇒12×40=AB⇒AB=20m

A kite is flying on a string of 40 m. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is $30^{\circ}$ . Find the height at which the kite is flying.
20

The correct option is A 20

AB is the height at which the kite is flying.
$s i n (∠ A C B) = \frac{A B}{A C} \Rightarrow s i n 30^{\circ} = \frac{A B}{A C} \Rightarrow \frac{1}{2} \times 40 = A B \Rightarrow A B = 20 m$