A kite is flying with a thread $200 m$ long. If the thread makes an angle of $50^{\circ}$ with the horizontal, find the height of the kite above the ground, assuming that there is no slack in the thread. [Use $sin 50^{\circ} = 0.766$ ]

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Solution

Let $A$ be the position of the kite at a height $A C .$

In $△ B C A,$

$sin 50^{\circ} = \frac{A C}{A B}$
$\Rightarrow 0.7660 = \frac{A C}{200}$
$\Rightarrow A C = 0.7660 \times 200$
$\Rightarrow A C = 153.2 m$

$∴$ The height of the kite is equal to $153.2 m .$

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A kite is flying with a thread 200 m long. If the thread makes an angle of 50∘ with the horizontal, find the height of the kite above the ground, assuming that there is no slack in the thread. [Use sin50∘=0.766]

Let A be the position of the kite at a height AC.In △BCA,sin50∘=ACAB⇒0.7660=AC200⇒AC=0.7660×200⇒AC=153.2 m∴ The height of the kite is equal to 153.2 m.

A kite is flying with a thread $200 m$ long. If the thread makes an angle of $50^{\circ}$ with the horizontal, find the height of the kite above the ground, assuming that there is no slack in the thread. [Use $sin 50^{\circ} = 0.766$ ]

Let $A$ be the position of the kite at a height $A C .$

In $△ B C A,$

$sin 50^{\circ} = \frac{A C}{A B}$
$\Rightarrow 0.7660 = \frac{A C}{200}$
$\Rightarrow A C = 0.7660 \times 200$
$\Rightarrow A C = 153.2 m$

$∴$ The height of the kite is equal to $153.2 m .$