Question

A kite maker made $1500$ kites for Independence day celebration. If $275$ kites were sold, how many kites were left?

Answer 1

Total number of kites $=1500$

Number of sold kites $=275$

Step 1: Subtract the ones

Given : $ThH\mathrm{T}\mathrm{O}1500-275$

As $5$ can not subtracted from $0$,

so, take $1$ carry from tens

now, $0$ becomes $10$ ( as $1$carry taken from tens )

First subtract ones $10-5=5$,

Write $5$ under ones column

Step 2: Subtract the tens

$0$ becomes $9$ in hundreds ( as $1$ carry taken by ones)

Next subtract tens $9-7=2$,

Write $2$ under tens column

Step 3: subtract the hundreds

$5$ becomes $4$ in hundreds ( as $1$ carry taken by tens)$1$

Next subtract hundreds $4-2=2$,

Write $2$ under hundreds column

Step 4 : Subtract the thousands

Next subtract $1-0=1$

Write $1$under thousands column

So we get,

Number of kites left $=$$ThH\mathrm{T}\mathrm{O}\text{Carry over}49101\cancel{5}\cancel{0}\cancel{0}-2751225$

Hence, the required solution is $1225$