A labourer has to put 90 bricks in equal piles.What are the different piles of equal number that he can make?

Open in App

Solution

30 bricks in 3 piles.
9 bricks in 10 piles.
10 bricks in 9 piles.
3 bricks in 30 piles.
45 bricks in 2 piles.
2 bricks in 45 piles.
6 bricks in 15 piles.
15 bricks in 6 piles.

Suggest Corrections

Similar questions

There are N number of gold biscuits in the house, in which four people live. If the first man woke up and divided the biscuits into 5 equal piles and found one extra biscuit. He took one of those piles along with the extra biscuit and hid them. He then gathered the 4 remaining piles into a big pile, woke up the second person and went to sleep. Each of the other 3 persons did the same one by one i.e. divided the big pile into 5 equal piles and found one extra biscuit. Each hid one of the piles along with the extra biscuit and gathered the remaining 4 piles into a big pile.
What is the sum of the number of biscuits hidden by the last 2 men?

There are N numbers of gold biscuits in the house, in which four people are lived. If the first men woke up and divided the biscuits into 5 equal piles and found one extra biscuit. He took one of those piles along with the extra biscuit and hid them. He then gathered the 4 remaining piles into a big pile, woke up the second person and went to sleep. Each of the other 3 persons did the same one by one, i.e., divided the big pile into 5 equal piles and found one extra biscuit. Each hid one of the piles along with the extra biscuit and gathered the remaining 4 piles into a big pile. If N $>$ 1000, what could be the least value of N?

There are N numbers of gold biscuits in the house, in which four people are lived. If the first man woke up and divided the biscuits into 5 equal piles and found one extra biscuit. He took one of those piles along with the extra biscuit and hid them. He then gathered the 4 remaining piles into a big pile, woke up the second person and went to sleep. Each of the other 3 persons did the same one by one i.e. divided the big pile into 5 equal piles and found one extra biscuit. Each hid one of the piles along with the extra biscuit and gathered the remaining 4 piles into a big pile.If N<1000, how many biscuits were left after the fourth man took his share?

Q. Select the number of brick piles that cannot be divided into any number of boxes except for 1 and itself.

Q. For the soil profile shown in figure below, the minimum number of precast concrete piles of

300 mm

diameter required to safely carry the load fo a given factor of safety of 2.5 (assuming

100 %

efficiency for the pile group) is equal to

Join BYJU'S Learning Program

A labourer has to put 90 bricks in equal piles.What are the different piles of equal number that he can make?

30 bricks in 3 piles. 9 bricks in 10 piles. 10 bricks in 9 piles. 3 bricks in 30 piles. 45 bricks in 2 piles. 2 bricks in 45 piles. 6 bricks in 15 piles. 15 bricks in 6 piles.

30 bricks in 3 piles.
9 bricks in 10 piles.
10 bricks in 9 piles.
3 bricks in 30 piles.
45 bricks in 2 piles.
2 bricks in 45 piles.
6 bricks in 15 piles.
15 bricks in 6 piles.