Question

A laced column is designed to carry 1000 kN axial load .The design force (tension or compression) in the lacing bar will be ____kN.
$\left[\text{Take}\theta ={45}^{\circ }\text{and assume lacings}\text{are provided on two opposite planes}\right]$

Answer 1

V = 2.5% of 1000 kN = 25 kN
$F_{\text{Lacing}}=\frac{V}{2sin\theta }=\frac{25}{2\times \frac{1}{\sqrt{2}}}$
$=\frac{25}{\sqrt{2}}=17.678kN$