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Question

A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder from base of the wall.

A
8m
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B
6.5m
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C
7m
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D
6m
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Solution

The correct option is D 6m

Let BA be the wall and AC be the ladder.
Therefore, by Pythagoras theorem, we have,
AC2=AB2+BC2
102=82+BC2
BC2=10064
BC2=36
BC=6m
Therefore, the distance of the foot of the ladder from the base of the wall is 6m.

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