Distance between Two Points Using Pythagoras Theorem
A ladder 10 m...
Question
A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder from base of the wall.
A
8m
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B
6.5m
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C
7m
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D
6m
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Solution
The correct option is D6m
Let BA be the wall and AC be the ladder. Therefore, by Pythagoras theorem, we have, AC2=AB2+BC2 102=82+BC2 BC2=100−64 BC2=36 BC=6m Therefore, the distance of the foot of the ladder from the base of the wall is 6m.