A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder from base of the wall.
The correct option is A6m
Let BA be the wall and AC be the ladder. Therefore, by Pythagoras theorem, we have, AC2=AB2+BC2 102=82+BC2 BC2=100−64 BC2=36 BC=6m Therefore, the distance of the foot of the ladder from the base of the wall is 6m.