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Question

A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder from base of the wall.
 
  1. 6m
  2. 8m
  3. 6.5m
  4. 7m


Solution

The correct option is A 6m

Let BA be the wall and AC be the ladder.
Therefore, by Pythagoras theorem, we have,
AC2=AB2+BC2
102=82+BC2
BC2=10064
BC2=36
BC=6m
Therefore, the distance of the foot of the ladder from the base of the wall is 6m.

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