A ladder 13 m long is placed on the ground in such a way that it touches the top of a vertical wall 12 m high. Find the distance of the foot of the ladder from the bottom of the wall.
A
3 m
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B
4 m
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C
5 m
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D
7 m
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Solution
The correct option is C 5 m According to the Pythagoras theorem , (perpendicular)2+(base)2=(hypotenuse)2 So, (base)2=(hypotenuse)2−(perpendicular)2=(13)2−(12)2=169−144=25 So, base= 5m.