A ladder $17 m$ long reaches a wall $15 m$ high. How far is the foot of the ladder from the wall.

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Solution

From figure,

Let the distance from foot of the ladder to the wall be $x$

$A O B$ is an right angle triangle,

So, $17^{2} = 15^{2} + x^{2}$

$⟹ x^{2} = 289 - 225$

$⟹ x^{2} = 64$

$⟹ x = 8 m .$

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A ladder 17 m long reaches a wall 15 m high. How far is the foot of the ladder from the wall.

From figure,Let the distance from foot of the ladder to the wall be xAOB is an right angle triangle,So, 172=152+x2⟹x2=289−225⟹x2=64⟹x=8m.

A ladder $17 m$ long reaches a wall $15 m$ high. How far is the foot of the ladder from the wall.

From figure,

Let the distance from foot of the ladder to the wall be $x$

$A O B$ is an right angle triangle,

So, $17^{2} = 15^{2} + x^{2}$

$⟹ x^{2} = 289 - 225$

$⟹ x^{2} = 64$

$⟹ x = 8 m .$