You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Law of Conservation of Mechanical Energy

A ladder 2.5 ...

Question

A ladder $2.5 m$ long and of weight $150 N$ has its centre of gravity $1 m$ from its bottom. A weight of $40 N$ is attached to the top end. The work done in raising the ladder from the horizontal to vertical position is

190 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

250 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

285 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

475 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $250 J$
Work done is equal to increase in potential energy in
(i) raising the weight $150 N$ of the ladder through a height $1 m$ and
(ii) raising a weight $40 N$ through $2.5 m$

$= 150 N \times 1 m + 40 N \times 2.5 m$
$= 250 N m = 250 J$

Suggest Corrections

Similar questions

Q. A ladder

A B

2.5 m

long and of weight

150 N

has its centre of gravity

1 m

from

A

is lying flat on ground.

A

weight of

40 N

is attached to the end

B

. The work required (in

j o u l e

) to raise the ladder from the horizontal position to vertical position so that the bottom end

A

is resting in a ditch

1 m

below the ground level will be :

Q. A ladder

^{'} A B^{'}

of weight

300 N

and length

5 m

is lying on a horizontal surface. Its centre of gravity is at a distance of

2 m

from end

A

. A weight of

80 N

is attached at end

B

. The work done in raising the ladder to the vertical position with end

^{'} A^{'}

in contact with the ground is.

Q. A ladder rests against frictionless vertical wall, with its upper end 6 m above the ground and the lower end 4 m away from the wall. The weight of the ladder is 500 N and its centre of gravity at

(1 / 3)^{r d}

distance from the lower end. Wall's reaction will be, in N

Q. A ladder

12 u n i t s

long slides in a vertical plane with its ends in contact with a vertical wall and a horizontal floor along x-axis. The locus of a point on the ladder 4 units from its one end has the equation :

Q. A long rod ABC of mass

m

and length

L

has two particles of masses

m

and

2 m

attached to it as shown in the figure. The system is initially in the horizontal position. The work to be done to keep it vertical with A at the bottom is (

g =

acceleration due to gravity)

Join BYJU'S Learning Program

A ladder 2.5 m long and of weight 150 N has its centre of gravity 1 m from its bottom. A weight of 40 N is attached to the top end. The work done in raising the ladder from the horizontal to vertical position is

The correct option is B 250 JWork done is equal to increase in potential energy in (i) raising the weight 150 N of the ladder through a height 1 m and (ii) raising a weight 40 N through 2.5 m =150 N×1 m+40 N×2.5 m =250 Nm=250 J

A ladder $2.5 m$ long and of weight $150 N$ has its centre of gravity $1 m$ from its bottom. A weight of $40 N$ is attached to the top end. The work done in raising the ladder from the horizontal to vertical position is

The correct option is B $250 J$
Work done is equal to increase in potential energy in
(i) raising the weight $150 N$ of the ladder through a height $1 m$ and
(ii) raising a weight $40 N$ through $2.5 m$

$= 150 N \times 1 m + 40 N \times 2.5 m$
$= 250 N m = 250 J$