A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder.

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Solution

Let AC be the ladder and BC be the wall . Then,
In right $△$ ABC,
$A C^{2} = A B^{2} + B C^{2}$
$A C^{2} = (2.5)^{2} + (6)^{2}$
$A C^{2} = 42.25$
$A C = 6.5 m$
Hence, the length of ladder is 6.5 m.

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A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder.

Let AC be the ladder and BC be the wall . Then,In right △ ABC,AC2=AB2+BC2AC2=(2.5)2+(6)2AC2=42.25AC=6.5 mHence, the length of ladder is 6.5 m.

Let AC be the ladder and BC be the wall . Then,
In right $△$ ABC,
$A C^{2} = A B^{2} + B C^{2}$
$A C^{2} = (2.5)^{2} + (6)^{2}$
$A C^{2} = 42.25$
$A C = 6.5 m$
Hence, the length of ladder is 6.5 m.