A ladder is placed against a wall such that its foot is at a distance of $3 m$ from the wall and its top reaches $4 m$ above the ground. Find the length of the ladder.

6.5

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$5 m$

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$25 m$

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$10 m$

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Solution

The correct option is B
$5 m$

By applying Pythagoras theorem in $△ A B C$

$A B^{2} + B C^{2} = A C^{2}$

$\Rightarrow 4^{2} + 3^{2} = A C^{2}$

$\Rightarrow A C^{2} = 25$

$\Rightarrow A C = 5 m$

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A ladder is placed against a wall such that its foot is at a distance of 3 m from the wall and its top reaches 4 m above the ground. Find the length of the ladder.

The correct option is B 5 m By applying Pythagoras theorem in △ABC AB2+BC2=AC2 ⇒42+32=AC2 ⇒AC2=25 ⇒AC=5 m

A ladder is placed against a wall such that its foot is at a distance of $3 m$ from the wall and its top reaches $4 m$ above the ground. Find the length of the ladder.

The correct option is B
$5 m$

By applying Pythagoras theorem in $△ A B C$

$A B^{2} + B C^{2} = A C^{2}$

$\Rightarrow 4^{2} + 3^{2} = A C^{2}$

$\Rightarrow A C^{2} = 25$

$\Rightarrow A C = 5 m$