A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches 6 m above the ground. Find the length of the ladder.

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Solution

We will apply pythagoras theorem

So $A B^{2}$ + $B C^{2}$ = $A C^{2}$

So AC = 6.5m

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A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches 6 m above the ground. Find the length of the ladder.

We will apply pythagoras theorem So AB2+BC2=AC2 So AC = 6.5m

We will apply pythagoras theorem

So $A B^{2}$ + $B C^{2}$ = $A C^{2}$

So AC = 6.5m