A ladder is placed along a wall of a house such that its upper end is touching the top of the wall. The foot of the ladder is 2 m away from the wall and the ladder is making an angle of $60^{\circ}$ with the level of the ground. Determine the height of the wall.

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Solution

Let AB be the wall of height h m and C be the points, makes an angle 60° and foot of the ladder is 2m away from the wall. We have to find height of wall

In a triangle ABC, given that BC = 2m and angle C = 60°

Now we have to find the height of wall.

So we use trigonometrically ratios.

In a triangle ABC,

$t a n C = \frac{A B}{B C}$

$t a n 60 = \frac{h}{2}$

$\sqrt{3} = \frac{h}{2}$

$h = 2 \sqrt{3}$

Hence height of wall is $2 \sqrt{3}$ meters.

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A ladder is placed along a wall of a house such that its upper end is touching the top of the wall. The foot of the ladder is 2 m away from the wall and the ladder is making an angle of 60∘ with the level of the ground. Determine the height of the wall.

A ladder is placed along a wall of a house such that its upper end is touching the top of the wall. The foot of the ladder is 2 m away from the wall and the ladder is making an angle of $60^{\circ}$ with the level of the ground. Determine the height of the wall.