A ladder of length 13 m rests against a wall. If it reaches a height of 12 m from the ground, then the distance of the foot of the ladder from the wall is ___ m.

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Solution

The correct option is B
5

Let the distance of the foot of the ladder from the wall = x
Using Pythagoras Theorem we have,

$x^{2} + 12^{2} = 13^{2}$

$x^{2} = 13^{2} - 12^{2}$

$x^{2} = (13 + 12) (13 - 12)$

$x^{2} = 25$

$x = 5 m$

Hence (B)

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A ladder of length 13 m rests against a wall. If it reaches a height of 12 m from the ground, then the distance of the foot of the ladder from the wall is ___ m.

The correct option is B 5 Let the distance of the foot of the ladder from the wall = x Using Pythagoras Theorem we have, x2+122=132 x2=132−122 x2=(13+12)(13–12) x2=25 x=5 m Hence (B)

The correct option is B
5

Let the distance of the foot of the ladder from the wall = x
Using Pythagoras Theorem we have,

$x^{2} + 12^{2} = 13^{2}$

$x^{2} = 13^{2} - 12^{2}$

$x^{2} = (13 + 12) (13 - 12)$

$x^{2} = 25$

$x = 5 m$

Hence (B)