A ladder of length 26m rests against a wall. If it reaches a height of 24 m from the ground, then the distance of the foot of the ladder from the wall is _________ m

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Solution

The correct option is D
10

Let the distance of the foot of the ladder from the wall = x m

Using Pythagoras Theorem we have,

$x^{2} + 24^{2} = 26^{2}$

$x^{2} = 26^{2} - 24^{2}$

$x^{2} = 676 - 576$

$x^{2} = 100$

$x = 10 m$

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A ladder of length 26m rests against a wall. If it reaches a height of 24 m from the ground, then the distance of the foot of the ladder from the wall is _________ m

The correct option is D 10 Let the distance of the foot of the ladder from the wall = x m Using Pythagoras Theorem we have, x2+242=262 x2=262−242 x2=676−576 x2=100 x=10m

The correct option is D
10

Let the distance of the foot of the ladder from the wall = x m

Using Pythagoras Theorem we have,

$x^{2} + 24^{2} = 26^{2}$

$x^{2} = 26^{2} - 24^{2}$

$x^{2} = 676 - 576$

$x^{2} = 100$

$x = 10 m$