Question

A ladder of length 41 m rests against a wall. If it reaches a height of 40 m from the ground, then the distance of the foot of the ladder from the wall is ___ m.

• A. 9
• B. 8
• C. 7
• D. 6

Answer 1

The correct option is A

9

Let the distance of the foot of the ladder from the wall = x
Using Pythagoras Theorem we have,

$x^2+{40}^2={41}^2$

$x^2={41}^2-{40}^2$

$x^2=1681-1600$

$x^2=81$

$x=9m$