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Question

A ladder of length L leans against a wall at an angle of θ from the horizontal, as shown in figure. The normal force FN applied from the ground on the ladder applies what torque about the ladders centre of mass?

632722_173b74f0b41c48ca828e249c3c70804b.png

A
FNL/2
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B
FNLcosθ
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C
FNLsinθ
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D
FNL/2cosθ
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Solution

The correct option is D FNL/2cosθ
The direction of normal force is shown in the shown in the attached figure. It has two components FNsinθ along the ladder and FNcosθ perpendicular to the rod. Torque is defined as moment of force. Hence, torque is given by:
τ=FNcosθL/2

673846_632722_ans_15cf7376cdce4d2493354ddb7fd43796.png

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