A ladder reaches a window 12 m above the ground and its foot is at distance of 5 m from a wall, then the length of the ladder is __ m.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
13

In the given figure, $△ A B C$ is right-angled.

From Pythagoras' theorem, we have

$A C^{2} = A B^{2} + B C^{2} .$

$\Rightarrow A C = \sqrt{A B^{2} + B C^{2}}$

$= \sqrt{12^{2} + 5^{2}}$

$= \sqrt{144 + 25}$

$= \sqrt{169}$

Thus, the length of the ladder is 13 m.

Suggest Corrections

Similar questions

Q. A ladder is placed in such a way that it's foot is at a distance of 12m from the wall and it's top reaches a window 5m above the ground. Find the length of the ladder.

Q. A ladder is placed in such a way that its foot is at a distance of

5 m

from a well and its top reaches a window

12 m

above the ground. Determine the length the ladder.

A ladder of length 13 m rests against a wall. If it reaches a height of 12 m from the ground, then the distance of the foot of the ladder from the wall is ___ m.

A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder. [3 MARKS]

Q. A 13 m long ladder reaches a window of a building 12 m above the ground. Determine the distance of the foot of the ladder from the building.

Join BYJU'S Learning Program

A ladder reaches a window 12 m above the ground and its foot is at distance of 5 m from a wall, then the length of the ladder is __ m.

The correct option is C 13 In the given figure, △ABC is right-angled. From Pythagoras' theorem, we have AC2=AB2+BC2. ⇒AC=√AB2+BC2 =√122+52 =√144+25 =√169 Thus, the length of the ladder is 13 m.

The correct option is C
13

In the given figure, $△ A B C$ is right-angled.

From Pythagoras' theorem, we have

$A C^{2} = A B^{2} + B C^{2} .$

$\Rightarrow A C = \sqrt{A B^{2} + B C^{2}}$

$= \sqrt{12^{2} + 5^{2}}$

$= \sqrt{144 + 25}$

$= \sqrt{169}$

Thus, the length of the ladder is 13 m.