Question

A ladder rests against frictionless vertical wall, with its upper end 6 m above the ground and the lower end 4 m away from the wall. The weight of the ladder is 500 N and its centre of gravity at $(1/3{)}^{rd}$ distance from the lower end. Wall's reaction will be, in N

• A. 111
• B. 333
• C. 222
• D. 129

Answer 1

The correct option is A 111

$N_1$=normal force from the wall to the ladder

$N_2$=normal force from the ground to the ladder

Let friction force due to the ground f pass through he contact point at the ground.

$A=$ angle made by ladder with wall

$\sin A=\frac{3}{\sqrt{13}}$

balancing forces;-

$N_2\times 6=500\times \frac{4}{3}$ (here $4/3$ m is the normal distance of the ground contact point to the line of weight action force.

$N_2=111.11$N

Hence, Option $A$ is correct.