A lady bought $50$ sweets at $20$ paise each $.$ In her house $,$ $10$ sweets were consumed $.$ She sold the remaining sweets at $40$ paise each $.$ What was her gain or loss percent $?$

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Solution

Step $1 :$ To find the loss or gain percent.
Cost price of $50$ sweets $=$ $50 \times 20$
$= 1000$ paise
Selling price of remaining sweets $= 40 \times 40$
$= 1600$
Step $2 :$ Now find the gain percent as $S . P . > C . P .$
Gain percent $= \frac{S . P . - C . P .}{C . P .} \times 100$
$= \frac{1600 - 1000}{1000} \times 100$
$= \frac{600}{1000} \times 100$
$= 60 %$
Hence, there will be a gain of $60 %$

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A lady bought 50 sweets at 20 paise each. In her house, 10 sweets were consumed. She sold the remaining sweets at 40 paise each. What was her gain or loss percent ?

Step 1: To find the loss or gain percent. Cost price of 50 sweets =50×20 =1000 paiseSelling price of remaining sweets =40×40 =1600Step 2: Now find the gain percent as S.P.>C.P.Gain percent =S.P.-C.P.C.P.×100 =1600-10001000×100 =6001000×100 =60%Hence, there will be a gain of 60%

A lady bought $50$ sweets at $20$ paise each $.$ In her house $,$ $10$ sweets were consumed $.$ She sold the remaining sweets at $40$ paise each $.$ What was her gain or loss percent $?$