A Lamp Post, $5 \sqrt{3} m$ high, cast a shadow $5 m$ long on the ground. The suns elevation of this point is:

30^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

45^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60^{\circ}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

90^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $60^{\circ}$

Let the angle of elevation be $^{'} θ^{'} .$
In, $△ A C B,$
$\Rightarrow tan θ = \frac{A B}{B C} = \frac{5 \sqrt{3}}{5}$
$\Rightarrow tan θ = \sqrt{3}$
$\Rightarrow$ Or $θ = 60^{\circ}$
Hence, the answer is $60^{\circ} .$

Suggest Corrections

Similar questions

Question 15
A pole 6m high casts a shadow $2 \sqrt{3} m$ long on the ground, then the Sun’s elevation is

(A) $60^{\circ}$
(B) $45^{\circ}$
(C) $30^{\circ}$
(D) $90^{\circ}$

A pole 6 m high casts a shadow $2 \sqrt{3}$ m long on the ground, then find the angle of elevation of the sun.

Find the angular elevation of the sun when a 10m long pole casts a shadow of length $10 \sqrt{3}$ m on the ground.

Q. A pole 6 m high casts a shadow

2 \sqrt{3}

m long on the ground. The sun's altitude is
(a) 30°
(b) 45°
(c) 60°
(d) 90°

Join BYJU'S Learning Program

A Lamp Post, 5√3m high, cast a shadow 5 m long on the ground. The suns elevation of this point is:

The correct option is C 60∘Let the angle of elevation be ′θ′.In, △ACB,⇒tanθ=ABBC=5√35⇒tanθ=√3⇒ Or θ=60∘Hence, the answer is 60∘.

A Lamp Post, $5 \sqrt{3} m$ high, cast a shadow $5 m$ long on the ground. The suns elevation of this point is:

The correct option is C $60^{\circ}$

Let the angle of elevation be $^{'} θ^{'} .$
In, $△ A C B,$
$\Rightarrow tan θ = \frac{A B}{B C} = \frac{5 \sqrt{3}}{5}$
$\Rightarrow tan θ = \sqrt{3}$
$\Rightarrow$ Or $θ = 60^{\circ}$
Hence, the answer is $60^{\circ} .$