Question

A landscaper is creating a rectangular flower bed such that the width is half of the length. The area of the flower bed is $34\mathrm{square}\mathrm{feet}$. Write and solve an equation to determine the width of the flower bed, to the nearest tenth of a foot.

Answer 1

Finding the width of the flower bed:

Given area of flower bed is $34\mathrm{square}\mathrm{feet}$such that the rectangular flower bed such that the width is half of the length.

$\therefore Length$$=2\times Width$

$\therefore$Area of rectangle $=Length\times Width$
$\Rightarrow$Area of rectangle$=$ $2\times Width\times Width$
$\Rightarrow$ $34=2\times {\left(\mathrm{Width}\right)}^2$
$\Rightarrow$ $\mathrm{Width}=\sqrt{\frac{34}{2}}$

$=4.123$
$\therefore$ $\mathrm{Width}\cong 4.1\mathrm{feet}$ (nearest tenth)

Hence, the width of the flower bed is $4.1\mathrm{feet}$.