Question

A large concave mirror has a radius of curvature of 1.5 m. A person stands 10 m in front of the mirror. Where is the person's image?

Answer 1

Given,

Radius of Curvature (R) = - 1.5 m(concave mirror)

Focal length = $\frac{R}{2}=\frac{-1.5}{2}=--0.75$ m

Object distance (u) = -10 m [Object distance is negative in Concave mirror]

Image distance (v) = ?

From the mirror formula

We know,

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

Putting all the values

$\frac{1}{v}-\frac{1}{10}=-\frac{1}{0.75}$

After solving

$v=\frac{-30}{37}=-0.81$ m

Hence the person's image will form at 0.81 m