A large glass slab $(μ = 5 / 3)$ of thickness $8$ cm is placed over a point source of light on a plane surface. It is seen that light emerges out of the top surface of the slab from a circular area of radius R cm. What is the value of R?

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Solution

$t a n c = \frac{R}{8}$
$\frac{4}{3} s i n c = 1 \times s i n 90^{o}$
$s i n c = \frac{3}{5}$
$C = 37^{o}$
$\frac{3}{4} = \frac{R}{8}$
$R = 6 c m$

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A large glass slab (μ=5/3) of thickness 8cm is placed over a point source of light on a plane surface. It is seen that light emerges out of the top surface of the slab from a circular area of radius R cm. What is the value of R?

tanc=R843sinc=1×sin90osinc=35C=37o34=R8R=6cm

A large glass slab $(μ = 5 / 3)$ of thickness $8$ cm is placed over a point source of light on a plane surface. It is seen that light emerges out of the top surface of the slab from a circular area of radius R cm. What is the value of R?

$t a n c = \frac{R}{8}$
$\frac{4}{3} s i n c = 1 \times s i n 90^{o}$
$s i n c = \frac{3}{5}$
$C = 37^{o}$
$\frac{3}{4} = \frac{R}{8}$
$R = 6 c m$