A large horizontal surface moves up and down in S.H.M. with an amplitude of 1cm. If a mass of 10kg (which is placed on the surface 0 is to remain continuously in contact with it, the maximum frequency of S.H.M. will be
A
5Hz
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B
0.5Hz
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C
1.5Hz
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D
10Hz
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Solution
The correct option is A5Hz Frequency of SHM, v=12π√accelerationdisplacement=12π√ax ⇒v=12π√km ⇒km=ax⇒ka=mx⇒v=12π√mx v=12π√1010−2=√1032π=10√102π=10×3.162×3.14=5Hz