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Question

A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water. The quantities of water flowing out per second from both holes are the same. Then, R is equal to

A
L2π
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B
2πL
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C
L
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D
12π
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Solution

The correct option is A L2π
Velocity of water coming out of square hole, v=2gy
Velocity of water coming out of circular hole, v=2g×4y=22gy
Now, vL2=vπR22gy×L2=22gy×πR2R=L2π

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