Question

A large pizza has a circumference of 88 inches. What will be the smallest area of the box holding the pizza? [4 MARKS]

Answer 1

Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark

Circumference of a circle

= $2\times \pi \times r=d\times \pi =88inches$

Where, d = diameter and $\pi =\frac{22}{7}$

$\Rightarrow 88=\frac{22}{7}\times d$

$\Rightarrow d=\frac{88\times 7}{22}$

$\Rightarrow d=28inches$

The diameter of the pizza will be equal to the length of the side of the box.

Side of box = 28 inches

Area of the box = (side)${}^2$ = (28 inches)${}^2$ = 784 inches${}^2$