A large sheet of uniform charge passes through a hypothetical spherical surface. The figure shows principle section of situation. The electric flux through the spherical surface is given by
A
πR2σϵ0`
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B
2π(R2−x2)σϵ0
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C
π(R−x)2σϵ0
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D
π(R2−x2)σϵ0
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Solution
The correct option is Dπ(R2−x2)σϵ0
The Gaussian surface marks a circle around the plane with radius r2=R2−x2.