CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A large steel wheel is to be fitted on to a shaft of the same material. At 27 °C, the outer diameter of the shaft is 8.70 cm and the diameter of the central hole in the wheel is 8.69 cm. The shaft is cooled using ‘dry ice’. At what temperature of the shaft does the wheel slip on the shaft? Assume coefficient of linear expansion of the steel to be constant over the required temperature range : α steel = 1.20 × 10¯⁵ K¯¹.

Open in App
Solution

Given that

At temperature T 1 =27 o C diameter of outer shaft D 1 =8.70cm

At temperature T 2 , the diameter of the shaft changes to D 2 =8.69cm

Coefficient of linear expansion, α=1.2× 10 5 K -1

Change in diameter is given by relation,

ΔD= D 1 αΔT D 2 D 1 = D 1 αΔT

Substitute the values.

8.698.70=8.70×1.2× 10 5 ×( T 2 27 ) ( T 2 27 )=95.78 T 2 =68.8 o C69 o C

Thus, the wheel can slip on the shaft when the shaft is cooled to a temperature of 69°C.


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermal Expansion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon