Question

A large water melon weights $20$ kg with $96\%$ of its weight being water. It is allowed to stand in the Sun and some of the water evaporates, so that now only $95$ $\%$ of its weight is water. Its reduced weight will be

• A. $18kg$
• B. $17kg$
• C. $16.5kg$
• D. $16kg$

Answer 1

The correct option is D $16kg$

Weight of water in the $20$ kg. water - melon
$=\frac{96\times 20}{100}=19.$ kg
Weight of water-melon pulp $=20$ kg $-19.2$ kg $= 0.8$ kg
Let the reduced weight of the water-melon be $x$ kg

Then weight of water in the water-melon after evaporation $=95\%$
evaporation $=95\%$
$\Rightarrow$ Weight of pulp $=5\%$
$\therefore$ $5\%$ of $x=0.8$ kg $\Rightarrow$ $x=$ $\frac{0.8\times 100}{5}=16$ kg