A larger drop is made from the two small drops each having 100V then voltage on the bigger drop is:
A
100 volt
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B
1000 volt
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C
156 volt
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D
100×223volt
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Solution
The correct option is D100×223volt let the radius of each drop be r and the resultant larger drop be R, then 2×43πr3=43πR3⇒R=213r100=kqrtotalchargeonthebiggerdrop=2qvoltageonthebiggerdropisk×2qR=2kq213r=223×100V