A laser signal sent towards the moon returns after t seconds.If c is speed of light, then the distance of the moon from the observer is

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c t^{- 1}

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c t^{- 2}

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\frac{c t}{2}

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Solution

The correct option is D $\frac{c t}{2}$
A laser signal sent towards the moon returns after t seconds.
Time taken to reach moon is $\frac{t i m e}{2} = \frac{t}{2}$
Therefore $d i s t a n c e = s p e e d * t i m e = c * \frac{t}{2}$

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A laser signal sent towards the moon returns after t seconds.If c is speed of light, then the distance of the moon from the observer is

The correct option is D ct2A laser signal sent towards the moon returns after t seconds.Time taken to reach moon is time2=t2Therefore distance=speed∗time=c∗t2

The correct option is D $\frac{c t}{2}$
A laser signal sent towards the moon returns after t seconds.
Time taken to reach moon is $\frac{t i m e}{2} = \frac{t}{2}$
Therefore $d i s t a n c e = s p e e d * t i m e = c * \frac{t}{2}$