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Question

A laser used to weld detached retinas emits light with a wavelength of 652nm in pulses that are 20.0ms in duration. The average power during each pulse is 0.6W. Then

A
The energy of each photon is 3.048×1019J
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B
The energy content in each pulse is 12mJ
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C
The number of photons in each pulse is nearly 4×1015
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D
The energy of each photon is nearly 1.9eV
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Solution

The correct options are
C The energy content in each pulse is 12mJ
D The energy of each photon is nearly 1.9eV
Energy of a photon is given by:

E=hcλ=6.63×1034×3×108652×109

E=3.048×1019J Thus, option A is incorrect.
Energy content in each pulse is given by
Ep=Power×20×103=12mJ Thus, option B is correct.
Number of photons can be obtained using

n=12×1033.048×1019=3.94×1016 Thus, option C is also incorrect.

Energy of each photon in eV is given as
E=3.048×1019×6.24×1018eV=1.9eV Thus, option D is correct.

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