A lateral faces of a square pyramid are equilateral triangles of side 30 centimetres. What is its surface area?

Open in App

Solution

Side of the equilateral triangle = 30 cm

Side of the square = Side of the equilateral triangle = 30 cm

Area of the square = (side)² = (30 cm)² = 900 cm²

Area of one equilateral triangle =

Area of four equilateral triangles =

Surface area of the square pyramid = Area of square + Area of four equilateral triangles

= (900 + ₎cm²

Suggest Corrections

Similar questions

Q. What is the total surface area of the square pyramid whose base edge is 6 cm long and the lateral faces are equilateral triangles?

Q. All the edges of a square pyramid are length

12

centimetre.
(a) What is the area of one lateral face of it?
(b) What is the surface area of this pyramid?
(c) Prove that the square of any term of this sequence is also a term of it.

The lateral surface area of a square pyramid comprises of equilateral triangles and the length of the lateral edge is $50 c m$ . What is its lateral surface area?

What is the total surface area of the square pyramid whose base edge is 6 cm long and the lateral faces are equilateral triangles?

The angle opposite to the base edge of a square pyramid on its lateral face is 30 $^{\circ}$ . If the slant height of the pyramid is 20 $c m$ , what is the lateral surface area of the pyramid? (Note that $t a n 15^{\circ} = 0.268$ )

Join BYJU'S Learning Program