Question

A lawn is rectangular in the middle, and it has semicircular portions along the shorter sides of the rectangle. The rectangular portion measures 50 m by 35 m. Find the area of the lawn.

Answer 1

Area of the rectangle = $50\times 35=1750{\mathrm{m}}^2$
Radius of the circle = 17.5 m
Area of the semicircle = $\frac{1}{2}{\mathrm{\pi r}}^2$

$$\begin{gathered} =\frac{1}{2}\times \frac{22}{7}\times 17.5\times 17.5 \\ =481.25{\mathrm{m}}^2 \end{gathered}$$

∴ Total area of the lawn = Area of the circle + Area of the two semicircles
$$\begin{gathered} =1750+481.25+481.25 \\ =2712.50{\mathrm{m}}^2 \end{gathered}$$