A lawn is the form of a square of side $30 m$ . A cow is tied with a rope of $10 m$ to a pole standing at one of its corners. The maximum area of the lawn grazed by this cow is

300 m^{2}

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150 m^{2}

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78.5 m^{2}

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450 m^{2}

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Solution

The correct option is D $78.5 m^{2}$
Area grazed by the cow
$= \frac{θ}{360^{0}} \times π r^{2} = \frac{90}{360} \times \frac{22}{7} \times 10 \times 10$

$= \frac{550}{7} = 78.5 m^{2}$

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A lawn is the form of a square of side 30m. A cow is tied with a rope of 10m to a pole standing at one of its corners. The maximum area of the lawn grazed by this cow is

The correct option is D 78.5m2Area grazed by the cow=θ3600×πr2=90360×227×10×10=5507=78.5m2

A lawn is the form of a square of side $30 m$ . A cow is tied with a rope of $10 m$ to a pole standing at one of its corners. The maximum area of the lawn grazed by this cow is

The correct option is D $78.5 m^{2}$
Area grazed by the cow
$= \frac{θ}{360^{0}} \times π r^{2} = \frac{90}{360} \times \frac{22}{7} \times 10 \times 10$

$= \frac{550}{7} = 78.5 m^{2}$