A layer of benzene (μ1=1.5)6cm deep floats on water (μ2=1.33)4cm deep. When viewed vertically through air the apparent distance of the bottom of the vessel below the top surface of the benzene will be -
A
14cm
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B
7cm
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C
21cm
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D
3.5cm
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Solution
The correct option is B7cm
Actual depth =d Apparent depth =dn Total length for benzene viewed from viewer =63/2=4cm For water =44/3=3cm So, apparent depth of bottom of vessel below the surface of benzene will be 4cm+3cm =7cm