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Question

A layer of benzene (μ1=1.5) 6 cm deep floats on water (μ2=1.33) 4 cm deep. When viewed vertically through air the apparent distance of the bottom of the vessel below the top surface of the benzene will be -

A
14 cm
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B
7 cm
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C
21 cm
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D
3.5 cm
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Solution

The correct option is B 7 cm

Actual depth =d
Apparent depth =dn
Total length for benzene viewed from viewer
=63/2=4 cm
For water =44/3=3 cm
So, apparent depth of bottom of vessel below the surface of benzene will be
4 cm+3 cm
=7 cm

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